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-4.9x^2+7x+265=0
a = -4.9; b = 7; c = +265;
Δ = b2-4ac
Δ = 72-4·(-4.9)·265
Δ = 5243
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5243}=\sqrt{49*107}=\sqrt{49}*\sqrt{107}=7\sqrt{107}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7\sqrt{107}}{2*-4.9}=\frac{-7-7\sqrt{107}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7\sqrt{107}}{2*-4.9}=\frac{-7+7\sqrt{107}}{-9.8} $
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